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人民币转换大写 python将人民币转换大写的脚本代码

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想了解python将人民币转换大写的脚本代码的相关内容吗,在本文为您仔细讲解人民币转换大写的相关知识和一些Code实例,欢迎阅读和指正,我们先划重点:人民币,转换大写,下面大家一起来学习吧。
复制代码 代码如下:

def Num2MoneyFormat( change_number ):
    """
    .转换数字为大写货币格式( format_word.__len__() - 3 + 2位小数 )
    change_number 支持 float, int, long, string
    """
    format_word = ["分", "角", "元",
               "拾","百","千","万",
               "拾","百","千","亿",
               "拾","百","千","万",
               "拾","百","千","兆"]

    format_num = ["零","壹","贰","叁","肆","伍","陆","柒","捌","玖"]
    if type( change_number ) == str:
        # - 如果是字符串,先尝试转换成float或int.
        if '.' in change_number:
            try:    change_number = float( change_number )
            except: raise ValueError, '%s   can\'t change'%change_number
        else:
            try:    change_number = int( change_number )
            except: raise ValueError, '%s   can\'t change'%change_number

    if type( change_number ) == float:
        real_numbers = []
        for i in range( len( format_word ) - 3, -3, -1 ):
            if change_number >= 10 ** i or i < 1:
                real_numbers.append( int( round( change_number/( 10**i ), 2)%10 ) )

    elif isinstance( change_number, (int, long) ):
        real_numbers = [ int( i ) for i in str( change_number ) + '00' ]

    else:
        raise ValueError, '%s   can\'t change'%change_number

    zflag = 0                       #标记连续0次数,以删除万字,或适时插入零字
    start = len(real_numbers) - 3
    change_words = []
    for i in range(start, -3, -1):  #使i对应实际位数,负数为角分
        if 0 <> real_numbers[start-i] or len(change_words) == 0:
            if zflag:
                change_words.append(format_num[0])
                zflag = 0
            change_words.append( format_num[ real_numbers[ start - i ] ] )
            change_words.append(format_word[i+2])

        elif 0 == i or (0 == i%4 and zflag < 3):    #控制 万/元
            change_words.append(format_word[i+2])
            zflag = 0
        else:
            zflag += 1

    if change_words[-1] not in ( format_word[0], format_word[1]):
        # - 最后两位非"角,分"则补"整"
        change_words.append("整")

    return ''.join(change_words)


Python 把金额小写转换成大写2

功能将小于十万亿元的小写金额转换为大写

复制代码 代码如下:

  def IIf( b, s1, s2):
  if b:
    return s1
  else:
    return s2
def num2chn(nin=None):
    cs =
('零','壹','贰','叁','肆','伍','陆','柒','捌','玖','◇','分','角','圆','拾','佰','仟',
'万','拾','佰','仟','亿','拾','佰','仟','万')
    st = ''; st1=''
    s = '%0.2f' % (nin)    
    sln =len(s)
    if sln >; 15: return None
    fg = (nin<1)
    for i in range(0, sln-3):
        ns = ord(s[sln-i-4]) - ord('0')
        st=IIf((ns==0)and(fg or (i==8)or(i==4)or(i==0)), '', cs[ns])
      + IIf((ns==0)and((i<>;8)and(i<>;4)and(i<>;0)or fg
and(i==0)),'', cs[i+13])
      + st
        fg = (ns==0)
    fg = False
    for i in [1,2]:
        ns = ord(s[sln-i]) - ord('0')
        st1 = IIf((ns==0)and((i==1)or(i==2)and(fg or (nin<1))), '', cs[ns])
       + IIf((ns>;0), cs[i+10], IIf((i==2) or fg, '', '整'))
       + st1
        fg = (ns==0)
    st.replace('亿万','万')
    return IIf( nin==0, '零', st + st1)
if __name__ == '__main__':
  num = 12340.1
  print num
  print num2chn(num)

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