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Android 警告( Android 出现的警告(Service Intent must be explicit)解决办法详解

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Android 出现的警告(Service Intent must be explicit)解决办法详解

有些时候我们使用Service的时需要采用隐私启动的方式,但是Android 5.0一出来后,其中有个特性就是Service Intent  must be explitict,也就是说从Lollipop开始,service服务必须采用显示方式启动。

而android源码是这样写的(源码位置:sdk/sources/android-21/android/app/ContextImpl.java):

private void validateServiceIntent(Intent service) {
  if (service.getComponent() == null && service.getPackage() == null) {
   if (getApplicationInfo().targetSdkVersion >= Build.VERSION_CODES.LOLLIPOP) {
    IllegalArgumentException ex = new IllegalArgumentException(
      "Service Intent must be explicit: " + service);
    throw ex;
   } else {
    Log.w(TAG, "Implicit intents with startService are not safe: " + service
      + " " + Debug.getCallers(2, 3));
   }
  }
 }

既然,源码里是这样写的,那么这里有两种解决方法:

1、设置Action和packageName:

参考代码如下:

Intent mIntent = new Intent();
mIntent.setAction("XXX.XXX.XXX");//你定义的service的action
mIntent.setPackage(getPackageName());//这里你需要设置你应用的包名
context.startService(mIntent);

此方式是google官方推荐使用的解决方法。

在此附上地址供大家参考:http://developer.android.com/goo ... tml#billing-service,有兴趣的可以去看看。

2、将隐式启动转换为显示启动:--参考地址:http://stackoverflow.com/a/26318757/1446466

public static Intent getExplicitIntent(Context context, Intent implicitIntent) {
  // Retrieve all services that can match the given intent
  PackageManager pm = context.getPackageManager();
  List<ResolveInfo> resolveInfo = pm.queryIntentServices(implicitIntent, 0);
  // Make sure only one match was found
  if (resolveInfo == null || resolveInfo.size() != 1) {
   return null;
  }
  // Get component info and create ComponentName
  ResolveInfo serviceInfo = resolveInfo.get(0);
  String packageName = serviceInfo.serviceInfo.packageName;
  String className = serviceInfo.serviceInfo.name;
  ComponentName component = new ComponentName(packageName, className);
  // Create a new intent. Use the old one for extras and such reuse
  Intent explicitIntent = new Intent(implicitIntent);
  // Set the component to be explicit
  explicitIntent.setComponent(component);
  return explicitIntent;
 }

调用方式如下:

Intent mIntent = new Intent();
mIntent.setAction("XXX.XXX.XXX");
Intent eintent = new Intent(getExplicitIntent(mContext,mIntent));
context.startService(eintent);

感谢阅读,希望能帮助到大家,谢谢大家对本站的支持!

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