Java递归求和1+2+3+...+n实例详解

public class Sum {
 
  public static int count(int n) {
 
    if (n > 1) {
      return count(n - 1) + n;
    } else {
      return n;
    }
  }
 
  public static void main(String[] args) {
    System.out.println(Sum.count(100));
  }
}

public class Demo1 {
	public static void main(String[] args) {
		System.out.print("请输入一个数：");
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		Sum(n);
		System.out.println(Sum(n));
	}
	private static int Sum(int n) {
		if (n == 0) {
			return 0;
		}
		return Sum(n - 1) + n;
	}
}