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Python 获取今天任意时刻的时间戳

是大嘟嘟呀 人气:0

代码

# -*- coding: utf-8 -*-
# Author    : markadc

from datetime import datetime, timedelta


# 获取今天任意时刻的时间戳
def today_anytime_tsp(hour, minute, second=0):
    now = datetime.now()
    today_0 = now - timedelta(hours=now.hour, minutes=now.minute, seconds=now.second)
    today_anytime = today_0 + timedelta(hours=hour, minutes=minute, seconds=second)
    tsp = today_anytime.timestamp()
    print('{}  的时间戳是  {}'.format(today_anytime, tsp))
    return tsp


if __name__ == '__main__':
    tsp = today_anytime_tsp(18, 15, 23)  # 获取今天18点15分23秒的时间戳
    print(tsp)

 输出

ps:Python来获取昨天和今天的日期

这个问题也是常见问题,可能碰到这种问题我们就会这么写yesterday = today - 1,tomorrow = today + 1;这样写实际会报错,会提示不支持的操作类型。碰到时间差的问题的,优先考虑datetime模块中的timedelta。具体获取很简单

>>> import datetime
>>> today = datetime.date.today()                   # 今天
>>> yesterday = today - datetime.timedelta(days=1)  # 昨天
>>> tomorrow = today + datetime.timedelta(days=1)   # 明天
>>> print(yesterday,today,tomorrow)
(datetime.date(2018, 7, 31), datetime.date(2018, 8, 1), datetime.date(2018, 8, 2))
>>>

其他的也可以获取一秒后,一分钟,一小时,甚至一年的具体日期

>>> import datetime
>>> t1 = datetime.datetime.today()                  # 获取现在时间
>>> t1
datetime.datetime(2018, 8, 1, 21, 34, 19, 924000)  
>>> t2 = t1 + datetime.timedelta(seconds=1)         # 获取一秒后的时间
>>> t2
datetime.datetime(2018, 8, 1, 21, 34, 20, 924000)  
>>> t3 = t1 + datetime.timedelta(seconds=60)        # 获取一分后的时间
>>> t3
datetime.datetime(2018, 8, 1, 21, 35, 19, 924000)
>>> t4 = t1 + datetime.timedelta(seconds=3600)      # 获取一小时后的时间
>>> t4
datetime.datetime(2018, 8, 1, 22, 34, 19, 924000)
>>> today = datetime.date.today()                   # 获取当前日期
>>> anday = today + datetime.timedelta(days=365)    # 获取一年后日期
>>> print(anday)
2019-08-01
>>>

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